9x^2+8x+4=140

Solution for 9x^2+8x+4=140 equation:

9x^2+8x+4=140

We move all terms to the left:

9x^2+8x+4-(140)=0

We add all the numbers together, and all the variables

9x^2+8x-136=0

a = 9; b = 8; c = -136;
Δ = b2-4ac
Δ = 82-4·9·(-136)
Δ = 4960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4960}=\sqrt{16*310}=\sqrt{16}*\sqrt{310}=4\sqrt{310}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{310}}{2*9}=\frac{-8-4\sqrt{310}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{310}}{2*9}=\frac{-8+4\sqrt{310}}{18}
$